C++ Institute CPA 問題集

質問 1：
What will the variable "age" be in class B?
class A { int x; protected:
int y;
public:
int age;
};
class B : private A {
string name;
public:
void Print() {
cout << name << age;
}
};
A. public
B. protected
C. None of these
D. private
正解：D

質問 2：
What will the variable "y" be in class B?
class A {
int x;
protected:
int y;
public:
int age;
};
class B : protected A {
string name;
public:
void Print() {
cout << name << age;
}
};
A. public
B. protected
C. None of these
D. private
正解：B

質問 3：
What happens when you attempt to compile and run the following code?
#include <iostream> #include <string>
using namespace std;
int main()
{
string s1[]= {"How" , "to" };
s1[0].swap(s1[1]);
for (int i=0; i<2; i++) {
cout << s1[i];
}
return( 0 );
}
A. It prints: toHow
B. It prints: Hoto
C. It prints: to
D. It prints: Ht
正解：A

質問 4：
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main(){
int *i;
i = new int;
*i = 1.0 / 2 * 2 / 1 * 2 / 4 * 4;
cout << *i;
return 0;
}
A. It prints: 2
B. It prints: 0
C. It prints: 1
D. It prints: 0.5
正解：A

質問 5：
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class complex{
double re, im;
public:
complex() : re(1),im(0.4) {}
complex operator?(complex &t);
void Print() { cout << re << " " << im; }
};
complex complex::operator? (complex &t){
complex temp;
temp.re = this->re ? t.re;
temp.im = this->im ? t.im;
return temp;
}
int main(){
complex c1,c2,c3;
c3 = c1 ? c2;
c3.Print();
}
A. It prints: 0 0
B. It prints: 2 0.8
C. It prints: 1 0.4
D. It prints: 1 0.8
正解：A

質問 6：
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main (int argc, const char * argv[])
{
int tab[5]={1,2,3};
for (int i=0; i<5; i++)
cout <<tab[i];
return 0;
}
A. It prints: 12345
B. It prints: 00000
C. It prints: 12300
D. compilation fails
正解：C

質問 7：
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int *t;
t = new int[2];
for (int i=0; i<2; i++) {
t[i] = i;
}
cout << t[1];
}
A. It prints: 10
B. It prints: 0
C. It prints: 1
D. It prints: ?1
正解：C

質問 8：
What will happen when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int getValue();
int main()
{
const int x = getValue();
cout<<x;
return 0;
}
int getValue()
{
return 5;
}
A. It will print 5
B. It will print garbage value
C. The code will not compile.
D. It will print 0
正解：A