Oracle 1Z0-803日本語 問題集

質問 1：

public class Painting {
private String type;
public String getType() {
return type;
}
public void setType(String type) {
this.type = type;
}
public static void main(String[] args) {
Painting obj1 = new Painting();
Painting obj2 = new Painting();
obj1.setType(null);
obj2.setType("Fresco");
System.out.print(obj1.getType() + " : " + obj2.getType());
}
}

A. Option A
B. Option C
C. Option D
D. Option B
正解：D

質問 2：

public class DoBreak1 {
public static void main(String[] args) {
String[] table = {"aa", "bb", "cc", "dd"};
for (String ss: table) {
if ( "bb".equals(ss)) {
continue;
}
System.out.println(ss);
if ( "cc".equals(ss)) {
break;
}
}
} }

A. Option E
B. Option A
C. Option C
D. Option D
E. Option B
正解：B

質問 3：



A. Option E
B. Option A
C. Option C
D. Option D
E. Option B
正解：D

質問 4：

public class Test {
public static void main(String[] args) {
Test t = new Test();
int[] arr = new int[10];
arr = t.subArray(arr,0,2);
}
// insert code here
}

A. public int[] subArray(int src, int start, int end) {
return src;
}
B. public int subArray(int src, int start, int end) {
return src;
}
C. public int[] subArray(int[] src, int start, int end) {
return src;
}
D. public int subArray(int[] src, int start, int end) {
return src;
}
正解：C

質問 5：
Given:
interface Pet { }
class Dog implements Pet { }
public class Beagle extends Dog{ }

A. Beagle c = new Dog();
B. Dog d = new Beagle();
C. Pet e = new Beagle();
D. Dog f = new Pet();
E. Pet a = new Dog();
F. Pet b = new Pet();
正解：B,C,E

質問 6：


A. A+ +, - - b
B. + +a, - -b
C. + +a, b-
D. A + +, b -
正解：C